Python program to specify Number of integers and Sort them in Ascending order

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Python program to specify Number of integers and Sort them in Ascending order

Below is the Python program that given a list of integers, SORTS them in Ascending Order (smallest to largest in a comma-separated list). The program expects a positive Integer as the Input to the “Number of integers to enter“, and exits gracefully with a custom message “The value you entered is a non-Integer OR -ve Integer!” otherwise. The program also checks if the numbers entered are positive integers and rejects any other type, requesting the user for a positive Integer instead!

 

#!/usr/bin/python3

numberCount = 0
total =0
average = 0
integerList = []
n = 0
greatestNumber = 0

upperLimit = input("How many integers do you want enter to Sort them in Ascending order?: ")

if upperLimit.isdigit() == True:

    upperLimit = int(upperLimit) 

    print("Please enter {} integers to sort them in Ascending order!\n\n".format(upperLimit))


    while numberCount < upperLimit:
     
        number = input("Enter number:")
     
        try:
        
            number = float(number) 
     
            if number.is_integer():
      
                number = int(number)

                integerList.append(number)

                numberCount += 1

                integerList.sort()

        except:
                
            print("You entered a non-Integer, instead enter a +ve/-ve Integer!") 


    print("\n\nYou entered {} integers and this is the list in a Ascending order: ".format(upperLimit) + str(integerList) + "!")

else: 
    print("The value you entered is a non-Integer OR -ve Integer!")

 

Python program to specify Number of integers and Sort them in Ascending order
Python | thetqweb